CLASS EXERCISE C21
Write a program in C that prompts the user for todays date,
calculates tomorrows date, and displays the result. Use
structures for todays date, tomorrows date, and an array to hold
the days for each month of the year. Remember to change the month
or year as necessary.
#include <stdio.h> struct date { int day, month, year; }; int days[] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 }; struct date today, tommorrow; void gettodaysdate( void ); void gettodaysdate( void ) { int valid = 0; while( valid == 0 ) { printf("Enter in the current year (1990-1999)-->"); scanf("&d", &today.year); if( (today.year < 1990) || (today.year > 1999) ) printf("\007Invalid year\n"); else valid = 1; } valid = 0; while( valid == 0 ) { printf("Enter in the current month (1-12)-->"); scanf("&d", &today.month); if( (today.month < 1) || (today.month > 12) ) printf("\007Invalid month\n"); else valid = 1; } valid = 0; while( valid == 0 ) { printf("Enter in the current day (1-%d)-->", days[today.month-1]); scanf("&d", &today.day); if( (today.day < 1) || (today.day > days[today.month-1]) ) printf("\007Invalid day\n"); else valid = 1; } } main() { gettodaysdate(); tommorrow = today; tommorrow.day++; if( tommorrow.day > days[tommorrow.month-1] ) { tommorrow.day = 1; tommorrow.month++; if( tommorrow.month > 12 ) { tommorrow.year++; tommorrow.month = 1; } } printf("Tommorrows date is %02d:%02d:%02d\n", \ tommorrow.day, tommorrow.month, tommorrow.year ); }